Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 236: 81

Answer

$\dfrac{x^{8}y^4}{z^{12}}$

Work Step by Step

Using $\left(\dfrac{a}{b}\right)^x=\dfrac{a^x}{b^x}$, then the expression, $ \left(\dfrac{x^2y}{z^3}\right)^4 $, simplifies to \begin{array}{l}\require{cancel} \dfrac{(x^2y)^4}{(z^3)^4} .\end{array} Using $(a^x)^y=a^{xy}$, then the given expression, $ \dfrac{(x^2y)^4}{(z^3)^4} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{x^{2(4)}y^4}{z^{3(4)}} \\\\= \dfrac{x^{8}y^4}{z^{12}} .\end{array}
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