Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set: 6

Answer

$\frac{13}{9}$

Work Step by Step

Any whole number raised to the power of zero is 1 while any number raised to a negative power is turned into that number's reciprocal with a positive exponent of the same value. Using these same rules, we obtain: $3^{0}+3^{-1}+3^{-2}$ =$1+\frac{1}{3}+\frac{1}{3^{2}}$ =$1+\frac{1}{3}+\frac{1}{9}$ =$\frac{1(9)+1(3)+1}{9}$ =$\frac{9+3+1}{9}$ =$\frac{13}{9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.