## Elementary Algebra

$\frac{5y}{2}$
We will simplify the expression by canceling out the common factors: $\frac{3x}{7y}\div\frac{6x}{35y^{2}}$ =$\frac{3x}{7y}\times\frac{35y^{2}}{6x}$ =$\frac{1x}{7y}\times\frac{35y^{2}}{2x}$ =$\frac{1x}{1y}\times\frac{5y^{2}}{2x}$ =$\frac{1}{1y}\times\frac{5y^{2}}{2}$ =$\frac{1}{1}\times\frac{5y^{2-1}}{2}$ =$\frac{5y^{1}}{2}$ =$\frac{5y}{2}$