## Elementary Algebra

$3(2x-3)(2x+3)$
Upon inspection, we find that $3$ is common to all the terms in the expression. Therefore we factor out $3$ from each term of the expression: $12x^{2}-27$ =$3(4x^{2}-9)$ Next, we further factor the quadratic equation within the parenthesis: $3(4x^{2}-9)$ =$3[(2x)^{2}-(3)^{2}]$ =$3(2x-3)(2x+3)$