Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set - Page 432: 33



Work Step by Step

Upon inspection, we find that $3$ is common to all the terms in the expression. Therefore we factor out $3$ from each term of the expression: $12x^{2}-27$ =$3(4x^{2}-9)$ Next, we further factor the quadratic equation within the parenthesis: $3(4x^{2}-9)$ =$3[(2x)^{2}-(3)^{2}]$ =$3(2x-3)(2x+3)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.