## Elementary Algebra

Multiplying the coefficients by each other and the radicals by each other, we obtain: $(3\sqrt 8)(4\sqrt 2)$ =$(3\sqrt 8)\times(4\sqrt 2)$ =$3(4)\times(\sqrt 2\times\sqrt 8)$ =$12\times(\sqrt {2\times8})$ =$12\times(\sqrt {16})$ =$12\times(\sqrt {4^{2}})$ =$12\times4$ =$48$