Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set: 44

Answer

48

Work Step by Step

Multiplying the coefficients by each other and the radicals by each other, we obtain: $(3\sqrt 8)(4\sqrt 2)$ =$(3\sqrt 8)\times(4\sqrt 2)$ =$3(4)\times(\sqrt 2\times\sqrt 8)$ =$12\times(\sqrt {2\times8})$ =$12\times(\sqrt {16})$ =$12\times(\sqrt {4^{2}})$ =$12\times4$ =$48$
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