## Elementary Algebra

$3x^{3}y^{6}-4y^{3}$
We factor $5x^{3}y^{2}$ from the numerator. Since $5x^{3}y^{2}$ is now common to both the numerator and the denominator, it is canceled and the resulting expression simplified. $\frac{15x^{6}y^{8}-20x^{3}y^{5}}{5x^{3}y^{2}}$ =$\frac{5x^{3}y^{2}(3x^{3}y^{6}-4y^{3})}{5x^{3}y^{2}}$ =$\frac{1(3x^{3}y^{6}-4y^{3})}{1}$ =$(3x^{3}y^{6}-4y^{3})$ =$3x^{3}y^{6}-4y^{3}$