Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set: 12

Answer

$\dfrac{-x+17}{(x-2)(x+3)}$

Work Step by Step

Using the $LCD= (x-2)(x+3) $, the given expression, $ \dfrac{3}{x-2}-\dfrac{4}{x+3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{(x+3)(3)-(x-2)(4)}{(x-2)(x+3)} \\\\= \dfrac{3x+9-4x+8}{(x-2)(x+3)} \\\\= \dfrac{-x+17}{(x-2)(x+3)} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.