## Elementary Algebra

$27x^{2}+30x-8$
Multiplying each term of the first parenthetical expression by the second parenthetical expression, we obtain: $(9x-2)(3x+4)$ =$9x(3x+4)-2(3x+4)$ =$27x^{2}+36x-6x-8$ =$27x^{2}+30x-8$