## Elementary Algebra

$2x(2x+5)(3x-4)$
Upon inspection, we find that the term $2x$ is common to all the terms in the expression. Therefore factor out $2x$ from each term of the expression to obtain: $12x^{3}+14x^{2}-40x$ =$2x(6x^{2}+7x-20)$ Next, we further factor the quadratic equation within the parenthesis: $2x(6x^{2}+7x-20)$ =$2x[(2x+5)(3x-4)]$ =$2x(2x+5)(3x-4)$