# Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set - Page 432: 32

$2x(2x+5)(3x-4)$

#### Work Step by Step

Upon inspection, we find that the term $2x$ is common to all the terms in the expression. Therefore factor out $2x$ from each term of the expression to obtain: $12x^{3}+14x^{2}-40x$ =$2x(6x^{2}+7x-20)$ Next, we further factor the quadratic equation within the parenthesis: $2x(6x^{2}+7x-20)$ =$2x[(2x+5)(3x-4)]$ =$2x(2x+5)(3x-4)$

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