Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 4 - Vector Spaces - 4.7 Change of Basis - Problems - Page 318: 7

Answer

$(-5,-\frac{5}{3},- \frac{5}{2})$

Work Step by Step

We know that $a(-1,0,0)+b(0,0,-3)+c(0,-2,0)=(5,5,5)$. Thus $-a=5 \\ -2c=5\\ -3b=5$. Thus $a=-5 \\ c= - \frac{5}{2} \\ b =-\frac{5}{3}$ Thus the vector is $(-5,-\frac{5}{3},- \frac{5}{2})$.
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