Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 4 - Vector Spaces - 4.7 Change of Basis - Problems - Page 318: 2



Work Step by Step

We know that $a(2,-2)+b(1,4)=(5,-10)$. Thus $2a+b=5$ and $-2a+4b=-10$. Thus $2a+4b+(-2a+b)=5+(-10)\\5b=-5\\b=-1$. Thus $2a+(-1)=5\\a=3$ Thus the vector is $(3,-1)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.