Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 4 - Vector Spaces - 4.7 Change of Basis - Problems - Page 318: 1

Answer

$(0,-3)$.

Work Step by Step

We know that $a(7,-1)+b(-9,-2)=(27,6)$. Thus $7a-9b=27$ and $-a-2b=6\\7a+14b=-42$. Thus $7a+14b-(7a-9b)=-42-27\\23b=-69\\b=-3$. Thus $7a-9(-3)=27\\7a=0\\a=0$ Thus the vector is $(0,-3)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.