Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 4 - Vector Spaces - 4.7 Change of Basis - Problems - Page 318: 3

Answer

$(-2,2)$.

Work Step by Step

We know that $a(-1,3)+b(3,2)=(8,-2)$. Thus $-a+3b=8\\-3a+9b=24$ and $3a+2b=-2$. Thus $-3a+9b+(3a+2b)=24+(-2)\\11b=22\\b=2$. Thus $3a+2(2)=-2\\a=-2$ Thus the vector is $(-2,2)$.
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