College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 30: 85


(a) $\frac{\sqrt{6}}{6}$ (b) $\frac{\sqrt{6}}{2}$ (c) $\frac{9\sqrt[4]{8}}{2}$

Work Step by Step

(a) $\frac{1}{\sqrt{6}}=\frac{1}{\sqrt{6}} \frac{\sqrt{6}}{\sqrt{6}}=\frac{\sqrt{6}}{6}$ (b)$\sqrt{\frac{3}{2}}=\frac{\sqrt{3}}{\sqrt{2}} \frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{6}}{2}$ (c) $\frac{9}{\sqrt[4]{2}}=\frac{9}{2^{1/4}} \frac{2^{3/4}}{2^{3/2}}=\frac{9\sqrt[4]{8}}{2}$
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