College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 85

Answer

(a) $\frac{\sqrt{6}}{6}$ (b) $\frac{\sqrt{6}}{2}$ (c) $\frac{9\sqrt[4]{8}}{2}$

Work Step by Step

(a) $\frac{1}{\sqrt{6}}=\frac{1}{\sqrt{6}} \frac{\sqrt{6}}{\sqrt{6}}=\frac{\sqrt{6}}{6}$ (b)$\sqrt{\frac{3}{2}}=\frac{\sqrt{3}}{\sqrt{2}} \frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{6}}{2}$ (c) $\frac{9}{\sqrt[4]{2}}=\frac{9}{2^{1/4}} \frac{2^{3/4}}{2^{3/2}}=\frac{9\sqrt[4]{8}}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.