#### Answer

$(y-1)\sqrt[3]{2y}$

#### Work Step by Step

Factor each radicand so that one of the factors is a perfect cube to obtain:
$=\sqrt[3]{y^3(2y)} -\sqrt[3]{2y}$
Simplify each radical to obtain:
$=y\sqrt[3]{2y} -\sqrt[3]{2y}$
Combine like radicals to obtain:
$=(y-1)\sqrt[3]{2y}$