College Algebra 7th Edition

$s^{\frac{5}{4}}$
RECALL: (i) $\sqrt[n]{a^m} = a^{\frac{m}{n}}$ (ii) $(a^m)^n=a^{mn}$ (iii) $a^m \cdot a^n = a^{m+n}$ Use rule (i) above to obtain: $=\sqrt{s\cdot s^{\frac{3}{2}}}$ Use rule {iii) to obtain: $=\sqrt{s^{1+\frac{3}{2}}} \\=\sqrt{s^{\frac{2}{2}+\frac{3}{2}}} \\=\sqrt{s^{\frac{5}{2}}}$ Use rule (i) to obtain: $=(s^{\frac{5}{2}})^{\frac{1}{2}}$ Use rule (ii) above to obtain: $=s^{\frac{5}{2}\cdot \frac{1}{2}} \\=s^{\frac{5}{4}}$