College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 30: 40

Answer

$9\sqrt{3}$

Work Step by Step

Factor each radicand so that one of the factors is a perfect square to obtain: $=\sqrt{25(3)} + \sqrt{16(3)} \\=\sqrt{5^2(3)}+\sqrt{4^2(3)}$ Simplify each radical to obtain: $=5\sqrt{3} + 4\sqrt{3}$ Combine like radicals to obtain: $=(5+4)\sqrt{3} \\=9\sqrt{3}$
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