## College Algebra 7th Edition

(a) 5 (b) $\sqrt[5]{3}$ (c) 4
(a) $5^{2/3}*5^{1/3}=5^{2/3+1/3}=5^{1}=5$ (b) $\frac{3^{3/5}}{3^{2/5}}=3^{3/5-2/5}=\sqrt[5]{3}$ (c) $(\sqrt[3]{4})^{3}=(4^{1/3})^3=4$