## College Algebra 7th Edition

Using $x=3, y=4, z=-1$ and plugging into the equation, we get: $(9x)^{2/3}+(2y)^{2/3}+z^{2/3}=(9*3)^{2/3}+(2*4)^{2/3}+(-1)^{2/3}=(3^{3})^{2/3}+(2^{3})^{2/3}+(1)^{1/3}=3^{2}+2^{2}+1=9+4+1=14$