College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 57

Answer

14

Work Step by Step

Using $x=3, y=4, z=-1$ and plugging into the equation, we get: $(9x)^{2/3}+(2y)^{2/3}+z^{2/3}=(9*3)^{2/3}+(2*4)^{2/3}+(-1)^{2/3}=(3^{3})^{2/3}+(2^{3})^{2/3}+(1)^{1/3}=3^{2}+2^{2}+1=9+4+1=14$
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