College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 62

Answer

(a) $x^{5/4}$ (b) $\frac{4}{\sqrt[3]{y}}$

Work Step by Step

(a) $\displaystyle \frac{x^{3/4_{X}7/4}}{x^{5/4}}=x^{3/4+7/4-5/4}=x^{5/4}$ (b)$\displaystyle \frac{(2y^{4/3})^{2}y^{-2/3}}{y^{7/3}}=4y^{8/3-2/3-7/3}=4y^{-1/3}=\frac{4}{y^{1/3}}=\frac{4}{\sqrt[3]{y}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.