## College Algebra 7th Edition

$x^{\frac{5}{9}}$
The exponent of $x$ (which is 5) is lower then the index (9). This means that the radical is already in simplest form. RECALL: $\sqrt[n]{a^m} = a^{\frac{m}{n}}$ Thus, $\sqrt[9]{x^5} = x^{\frac{5}{9}}$