College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.2 - Systems of Linear Equations in Several Variables - 5.2 Exercises - Page 455: 40

Answer

$x=28000,$ $y=8000,$ $z=14000$

Work Step by Step

Account paying simple interest=$3\%$ Account paying simple interest=$5.5\%$ Account paying simple interest=$9\%$ let $x$ denote the account paying $3\%$, let $y$ denote the account paying $5.5\%$, let $z$ denote the account paying $9\%$. Thus, $x+y+z=50,000,$ denotes a formula the amount she invests and $0.03x+0.05.5y+0.09z=2540$ denotes a formula the amount it returns in a year. Whereas, $x=2z$. $\begin{cases} y+3z=50000\\ 0.055y+0.15z=2540\\ \end{cases}$ Multiplying Equation 2 by -20 and adding it to Equation 1. $\begin{cases} y+3z=50000\\ -0.1y-3z=-50800\\ -- -- -- -- --\\ -0.1y=-800 \end{cases}$ Thus, $y=8000$. Substituting it back in, $8000+3z=50000, z=14000$. Since $x=2z, x=28000$.
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