College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.2 - Systems of Linear Equations in Several Variables - 5.2 Exercises - Page 455: 15

Answer

$\begin{cases} 2x+y-3z=5\\ 2x+3y+z=13\\ 0x-14y-4z=-32 \end{cases}$

Work Step by Step

$\begin{cases} 2x+y-3z=5\\ 2x+3y+z=13\\ 6x-5y-z=7 \end{cases}$ Multiplying Equation 2 by $-3$ and adding it to Equation 3. results in a new Equation 3. $\begin{cases} -6x-9y-3z=-39\\ 6x-5y-z=7\\ -- -- -- --\\ 0x-14y-4z=-32 \end{cases}$ Therefore, The new equivalent system is.. $\begin{cases} 2x+y-3z=5\\ 2x+3y+z=13\\ 0x-14y-4z=-32 \end{cases}$
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