College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.2 - Systems of Linear Equations in Several Variables - 5.2 Exercises - Page 455: 35

Answer

$x=2-2t$ $y=-\frac{2}{3}+\frac{4}{3}t$ $z=t$

Work Step by Step

Step 1. $x+3y-2z=0$ $2x+4z=4$ Equation 2 $+$ $(-2)$ Equation 1 $4x+6y=4$ Equation 3 $+$ $(-4)$ Equation 1 Step 2. $x+3y-2z=0$ Equation 1 $+$ $\frac{1}{2}$ Equation 2 $-6y+8z=4$ Multiply by $-\frac{1}{6}$ $-6y+8z=4$ Equation 3 $+$ $(-1)$ Equation 2 Step 3. $x+2z=2$ $y-\frac{4}{3}z=-\frac{2}{3}$ Step 4. Let $z=t$ $x=2-2z=2-2t$ $y=-\frac{2}{3}+\frac{4}{3}z=-\frac{2}{3}+\frac{4}{3}t$ Step 5. Conclude the solution The solution is $x=2-2t$, $y=-\frac{2}{3}+\frac{4}{3}t$, $z=t$.
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