College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.2 - Systems of Linear Equations in Several Variables - 5.2 Exercises - Page 455: 14

Answer

$\begin{cases} -5x+2y-3z=3\\ 0x+y-5z=-14\\ -x+3y+z=8 \end{cases}$

Work Step by Step

$\begin{cases} -5x+2y-3z=3\\ 10x-3y+z=-20\\ -x+3y+z=8 \end{cases}$ Multiplying Equation 1 by 2 and adding it to Equation 2. results in a new Equation 2. $\begin{cases} -10x+4y-6z=6\\ 10x-3y+z=-20\\ -- -- -- -- -- \\ 0x+y-5z=-14 \end{cases}$. Therefore, The new equivalent Equation is... $\begin{cases} -5x+2y-3z=3\\ 0x+y-5z=-14\\ -x+3y+z=8 \end{cases}$
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