College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.2 - Systems of Linear Equations in Several Variables - 5.2 Exercises - Page 455: 39

Answer

$x=30000,$ $y=30000,$ $z=40000$

Work Step by Step

Short-term=$4\%$ Intermediate=$5\%$ Long-term=$6\%$ let $x$ denote the amount he invests in short-term, let $y$ denote the amont he invests in Intermediate let $z$ denote the amount he invests in long-term bond. Thus, $x+y+z=100,000,$ denotes a formula the amount he invests and $0.04x+0.05y+0.06z=100,000\times0.051$ denotes a formula the amount it returns in a year. Whereas, $x=y$. $\begin{cases} 2y+z=100000\\ 0.09y+0.06z=5100\\ \end{cases}$ Multiplying Equation 2 by -22.22.. and adding it to Equation 1. $\begin{cases} 2y+z=100000\\ -2y-1.33z=-113333.333\\ -- -- -- -- --\\ -0.333z=-13333.333 \end{cases}$ Thus, $z=40000$. Substituting it back in, $2y+40000=100000, y=30000$. Since $x=y, x=30000$.
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