College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.2 - Systems of Linear Equations in Several Variables - 5.2 Exercises - Page 455: 24

Answer

$x=-1,$ $y=1,$ $z=2$

Work Step by Step

$\begin{cases} x-y+2z=2\\ 3x+y+5z=8\\ 2x-y-2z=-7 \end{cases}$ Multiplying Equation 1 by -2 and adding it to Equation 3, results in new Equation 3. $\begin{cases} -2x+2y-4z=-4\\ 2x-y-2z=-7\\ -- -- -- -- --\\ y-6z=-11 \end{cases}$ Multiplying Equation 1 by -3 and adding it to Equation 2, results in new Equation 2. $\begin{cases} -3x+3y-6z=-6\\ 3x+y+5z=8\\ -- -- -- -- --\\ 4y-z=2 \end{cases}$ Multiplying new Equation 3 by -4 and adding it to new Equation 2. $\begin{cases} -4y+24z=44\\ 4y-z=2\\ -- -- --\\ 23z=46 \end{cases}$ Thus, $z=2$. Susbtituting it back into new Equation 3, $y-12=-11, y=1$. Substituting it back into Equation 1, $x-1+4=2, x=-1$
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