Answer
$x=\frac{1}{4},$
$y=\frac{1}{2},$
$z=-\frac{1}{2}$
Work Step by Step
$\begin{cases}
2y+4z=-1\\
-2x+y+2z=-1\\
4x-2y=0
\end{cases}$
Multiplying Equation 2 by 2 and adding it to Equation 3.
$\begin{cases}
-4x+2y+4z=-2\\
4x-2y=0\\
-- -- -- --\\
4z=-2
\end{cases}$
Thus, $z=-\frac{1}{2}$. Substituting back into Equation 1, $2y-2=-1, y=\frac{1}{2}$. Substituting back into Equation 3, $4x-1=0, x=\frac{1}{4}$
