College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Section 5.2 - Systems of Linear Equations in Several Variables - 5.2 Exercises - Page 455: 26

Answer

$x=-1,$ $y=-2,$ $z=4$

Work Step by Step

$\begin{cases} 2x+y-z=-8\\ -x+y+z=3\\ -2x+4z=18 \end{cases}$ Adding Equation 1 and Equation 3, results in new Equation 1. $\begin{cases} 2x+y-z=-8\\ -2x+4z=18\\ -- -- -- --\\ y+3z=10 \end{cases}$ Multiplying Equation 2 by -2 and adding it to Equation 3, results in new Equation 2. $\begin{cases} 2x-2y-2z=-6\\ -2x+4z=18\\ -- -- -- --\\ -2y+2z=12 \end{cases}$ Multiplying new Equation 1 by 2 and adding it to new Equation 2. $\begin{cases} -2y+2z=12\\ 2y+6z=20\\ -- -- --\\ 8z=32 \end{cases}$ Thus, $z=4$. Substituting it back into new Equation 1, $y+12=10, y=-2$. Substituting it back into Equation 2, $-x-2+4=3, x=-1$
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