#### Answer

$f(x)= \frac{2}{x^{2}}$
$g(x)=3+x$
$h(x)=\sqrt{x}$
Other answers are also possible.

#### Work Step by Step

If we let:
$f(x)= \frac{2}{x^{2}}$
$g(x)=3+x$
$h(x)=\sqrt{x}$
Then:
$(f\circ g\circ h)(x)=f(g(h(x))=f(3+\sqrt{x})=\frac{2}{(3+\sqrt{x})^{2}}=G(x)$
Other answers are also possible.