#### Answer

$\sqrt{\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1}}$

#### Work Step by Step

We are given: $f(x)=\sqrt{x},\ g(x)=\frac{x}{x-1},\ h(x)=\sqrt[3]{x}$
We evaluate:
$(f \circ g\circ h)(x)=f(g(h(x)))=
f(g(\sqrt[3]{x}))=f(\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1})=
\sqrt{\frac{\sqrt[3]{x}}{\sqrt[3]{x}-1}}$