College Algebra 7th Edition

Published by Brooks Cole

Chapter 2, Functions - Section 2.7 - Combining Functions - 2.7 Exercises - Page 253: 64

Answer

$f(x)=x+1$ And: $g(x)=\sqrt{x}$ Other answers are also possible.

Work Step by Step

We want: $F(x)=(f\circ g)(x)=f(g(x))$. We make: $f(x)=x+1$ And: $g(x)=\sqrt{x}$ Then: $f(g(x))=\sqrt{x}+1=F(x)$ Other answers are also possible.

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