College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.7 - Combining Functions - 2.7 Exercises: 68

Answer

$f(x)=\sqrt{1+x}$ And: $g(x)=\sqrt{x}$ Other answers are also possible.

Work Step by Step

We want: $H(x)=(f\circ g)(x)=f(g(x))$. We make: $f(x)=\sqrt{1+x}$ And: $g(x)=\sqrt{x}$ Then: $f(g(x))=\sqrt{1+\sqrt{x}}=H(x)$ Other answers are also possible.
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