## College Algebra 7th Edition

$f(x)=x^{9}$ $g(x)=4+x$ $h(x)=\sqrt[3]{x}$ Other answers are also possible.
If we let: $f(x)=x^{9}$ $g(x)=4+x$ $h(x)=\sqrt[3]{x}$ Then: $(f\circ g\circ h)(x)=f(g(h(x))=(4+\sqrt[3]{x})^{9}=G(x)$ Other answers are also possible.