#### Answer

1

#### Work Step by Step

From the table, we see that: $g(2)=5$ and $g(5)=1$, so we have:
$(g\circ g)(2)=g(g(2))=g(5)=1$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

1

From the table, we see that: $g(2)=5$ and $g(5)=1$, so we have:
$(g\circ g)(2)=g(g(2))=g(5)=1$

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