College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.7 - Combining Functions - 2.7 Exercises: 46

Answer

1

Work Step by Step

From the table, we see that: $g(2)=5$ and $g(5)=1$, so we have: $(g\circ g)(2)=g(g(2))=g(5)=1$
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