#### Answer

$f(x)=|x|$
And:
$g(x)=1-x^{3}$
Other answers are also possible.

#### Work Step by Step

We want: $H(x)=(f\circ g)(x)=f(g(x))$.
We make:
$f(x)=|x|$
And:
$g(x)=1-x^{3}$
Then:
$f(g(x))=|1-x^{3}|=H(x)$
Other answers are also possible.

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$f(x)=|x|$
And:
$g(x)=1-x^{3}$
Other answers are also possible.

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