## College Algebra 7th Edition

$f(x)= \frac{x}{x+4}$ And: $g(x)=x^{2}$ Other answers are also possible.
We want: $G(x)=(f\circ g)(x)=f(g(x))$. We make: $f(x)= \frac{x}{x+4}$ And: $g(x)=x^{2}$ Then: $f(g(x))=\frac{x^{2}}{x^{2}+4}=G(x)$ Other answers are also possible.