College Algebra 7th Edition

Published by Brooks Cole

Chapter 1, Equations and Graphs - Section 1.2 - Graphs of Equations in Two Variables; Circles - 1.2 Exercises: 74

Answer

$(x+1)^2+(y+3)^2=9$

Work Step by Step

RECALL: The standard form of a circle whose center is at $(h, k)$ and radius $r$ is $(x--h)^2+(y-k)^2=r^2$. The center is at $(-1, -3)$, then $h=-1$ and $k=-3$. The radius is 3 so $r=3$. Thus, the standard form of the given circle's equation of the circle is: $[x-(-1)]^2+[y-(-3)]^2=3^2 \\(x+1)^2+(y+3)^2=9$

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