## College Algebra 7th Edition

center: $(0, 0)$; radius = $\sqrt5$ units Refer to the image below for the graph.
RECALL: The circle $x^2+y^2=r^2$ has its center at $(0, 0)$ and a radius of $r$ units. The given circle can be written as $x^2+y^2=(\sqrt5)^2$. This equation is in the same form as the one in the recall part above so its center is at $(0, 0)$ and its radius is $\sqrt5$ units. Plot the points that are: $\sqrt5$ units above the center: $(0,$\sqrt5$)$ $\sqrt5$ units below the center: $(0, -$\sqrt5$)$ $\sqrt5$ units to the left of the center: $(-$\sqrt5$, 0)$ $\sqrt5$ units to the right of the center: $($\sqrt5$, 0)$ (note: $\sqrt5 \approx 2.236$) Then, connect the points using a curve to form a circle. (refer to the attached image in the answer part above)