#### Answer

center: $(-1, -2)$
radius: $6$ units
Refer to the image below for the graph.

#### Work Step by Step

RECALL:
The circle $(x--h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units.
The given equation can be written as $(x+1)^2+(y+2)^2=6^2$, which is in the same form as the one in the recall part above.
Thus, the circle has:
its center at $(-1, -2)$;
a radius of 6 units
Plot the center.
Then, plot the following points:
6 units above the center: $(-1, 4)$
6 units below the center: $(-1, -8)$
6 units to the left of the center: $(-7, -2)$
6 units to the right of the center: $(5, -2)$
Connect the four points (not including the center) using a curve to form a circle.