center: $(3, 0)$; radius = 4 units Refer to the image below for the graph.
Work Step by Step
RECALL: The circle $(x-h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units. The given circle can be written as $(x-3)^2+(y-0)^2=4^2$. This equation is in the same form as the one in the recall part above so its center is at $(3, 0)$ and its radius is $4$ units. Plot the center. Then, points that are: 4 units above the center: $(3, 4)$ 4 units below the center: $(3, -4)$ 4 units to the left of the center: $(-1, 0)$ 4 units to the right of the center: $(7, 0)$ Then, connect the points using a curve to form a circle. (refer to the attached image in the answer part above)