# Chapter 1, Equations and Graphs - Section 1.2 - Graphs of Equations in Two Variables; Circles - 1.2 Exercises - Page 102: 52

x-intercept: $-1$ y-intercept: $1$

#### Work Step by Step

RECALL: (1) A point where the graph touches or crosses the x-axis is called an x-intercept. Given an equation, the x-intercept/s can be found by setting $y=0$ then solving for $x$. (2) A point where the graph touches or crosses the y-axis is called a y-intercept. Given an equation, the y-intercept/s can be found by setting $x=0$ then solving for $y$. Solve for the x-intercept/s by setting $y=0$ then solving for $x$: $\begin{array}{ccc} &y &= &\sqrt{x+1} \\&0 &= &\sqrt{x+1} \\&0^2 &= &(\sqrt{x+1})^2 \\&0 &= &x+1 \\&0-1 &= &x+1-1 \\&-1 &= &x \end{array}$ The x-intercept is $-1$. Solve for the y-intercept/s by setting $x=0$ then solving for $y$: $\begin{array}{ccc} &y &= &\sqrt{x+1} \\&y &= &\sqrt{0+1} \\&y &= &\sqrt1 \\&y &= &1 \end{array}$ The y-intercept is $1$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.