## College Algebra 7th Edition

x-intercepts: $-5$ and $5$ y-intercepts: $-2$ and $2$
RECALL: (1) A point where the graph touches or crosses the x-axis is called an x-intercept. Given an equation, the x-intercept/s can be found by setting $y=0$ then solving for $x$. (2) A point where the graph touches or crosses the y-axis is called a y-intercept. Given an equation, the y-intercept/s can be found by setting $x=0$ then solving for $y$. Solve for the x-intercept/s by setting $y=0$ then solving for $x$: $\begin{array}{ccc} &4x^2+25y^2 &= &100 \\&4x^2+25(0^2) &= &100 \\&4x^2 &= &100 \\&\dfrac{4x^2}{4} &= &\dfrac{100}{4} \\&x^2 &= &25 \\&x &= &\pm\sqrt{25} \\&x &= &\pm\sqrt{5^2} \\&x &= &\pm 5 \end{array}$ The x-intercepts are $-5$ and $5$. Solve for the y-intercept/s by setting $x=0$ then solving for $y$: $\begin{array}{ccc} &4x^2+25y^2 &= &100 \\&4(0^2)+25y^2 &= &100 \\&25y^2 &= &100 \\&\dfrac{25y^2}{25} &= &\dfrac{100}{25} \\&y^2 &= &=4 \\&y &= &\pm\sqrt{4} \\&y &= &\pm\sqrt{2^2} \\&y &= &\pm 2 \end{array}$ The y-intercepts are $-2$ and $2$.