## College Algebra 7th Edition

Center: $(0, 2)$; radius = 2 units Refer to the image below for the graph.
RECALL: The circle $(x-h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units. The given circle can be written as $(x-0)^2+(y-2)^2=2^2$. This equation is in the same form as the one in the recall part above so its center is at $(0, 2)$ and its radius is $2$ units. Plot the center. Then, points that are: 2 units above the center: $(0, 4)$ 2 units below the center: $(0, 0)$ 2 units to the left of the center: $(-2, 2)$ 2 units to the right of the center: $(2, 2)$ Then, connect the points using a curve to form a circle. (refer to the attached image in the answer part above)