## College Algebra 7th Edition

$(x+3)^2+(y-2)^2=25$
RECALL: The standard form of a circle whose center is at $(h, k)$ and radius $r$ is $(x--h)^2+(y-k)^2=r^2$. With the center at $(-3, 2)$, then $h=-3$ and $k=2$. The radius is 5 so $r=5$. Thus, the standard form of the given circle's equation of the circle is: $[x-(-3)]^2+(y-2)^2=5^2 \\(x+3)^2+(y-2)^2=25$