#### Answer

$(x+3)^2+(y-2)^2=25$

#### Work Step by Step

RECALL:
The standard form of a circle whose center is at $(h, k)$ and radius $r$ is $(x--h)^2+(y-k)^2=r^2$.
With the center at $(-3, 2)$, then $h=-3$ and $k=2$.
The radius is 5 so $r=5$.
Thus, the standard form of the given circle's equation of the circle is:
$[x-(-3)]^2+(y-2)^2=5^2
\\(x+3)^2+(y-2)^2=25$