Answer
False,
$\ln(x\cdot 1)=\ln x+\ln 1$
Work Step by Step
On the RHS, the term ln1 equals zero,
(a basic logarithmic property,
so the equation of the problem statement is equivalent to
ln(x+1)=lnx,
which is false.
A property for expanding $\log_{b}(...sum...)$ does not exist.
There is, however, The Product Rule: $\log_{\mathrm{b}}(\mathrm{M}\mathrm{N})=\log_{\mathrm{b}}\mathrm{M}+\log_{\mathrm{b}}\mathrm{N}$
which has the same form of the RHS as the problem statement.
Therefore, a change making the statement true would be:
$\ln(x\cdot 1)=\ln x+\ln 1$
