## College Algebra (6th Edition)

Using the Change-of-Base Property, $\displaystyle \log_{b}M=\frac{\log_{a}M}{\log_{a}b}$, we want to change the base of the logarithm on the LHS from 3 to 7: b=3, M=7, a=7: $LHS=\displaystyle \log_{3}7=\frac{\log_{7}7}{\log_{7}3}$ = ... ... the numerator equals 1, by the basic property $\log_{b}b=1$, $=\displaystyle \frac{1}{\log_{7}3}=RHS,$ so the problem statement is true.