## College Algebra (6th Edition)

$log_{5}7+log_{5}3$
Based on the product rule of logarithms, we know that $log_{b}(MN)=log_{b}M+log_{b}N$ (for $M\gt0$ and $N\gt0$). Therefore, $log_{5}(7\times3)=log_{5}7+log_{5}3$.