Answer
$log_{7}7-log_{7}x$
Work Step by Step
Based on the quotient rule of logarithms, we know that $log_{b}(\frac{M}{N})=log_{b}M-log_{b}N$ (where $b$, $M$, and $N$ are positive real numbers and $b\ne1$).
Therefore, $log_{7}(\frac{7}{x})=log_{7}7-log_{7}x$.