Answer
$log(\frac{3x+7}{x})$
Work Step by Step
Based on the quotient rule of logarithms, we know that $log_{b}(\frac{M}{N})=log_{b}M-log_{b}N$ (where $b$, $M$, and $N$ are positive real numbers and $b\ne1$).
Therefore, $log(3x+7)-log(x)=log(\frac{3x+7}{x})$.
In this case, the given logarithm is a common logarithm, which has an understood base of 10.